Base | Representation |
---|---|
bin | 11110111011101010… |
… | …000010100101011101 |
3 | 10011201200100212121201 |
4 | 132323222002211131 |
5 | 1021010030143401 |
6 | 23131412355501 |
7 | 2254023646003 |
oct | 367352024535 |
9 | 104650325551 |
10 | 33213131101 |
11 | 130a3a45a87 |
12 | 652b015b91 |
13 | 3193c806c7 |
14 | 1871090a73 |
15 | ce5c6cb01 |
hex | 7bba8295d |
33213131101 has 2 divisors, whose sum is σ = 33213131102. Its totient is φ = 33213131100.
The previous prime is 33213131069. The next prime is 33213131111. The reversal of 33213131101 is 10113131233.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32735664900 + 477466201 = 180930^2 + 21851^2 .
It is a cyclic number.
It is not a de Polignac number, because 33213131101 - 25 = 33213131069 is a prime.
It is a super-2 number, since 2×332131311012 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33213131111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16606565550 + 16606565551.
It is an arithmetic number, because the mean of its divisors is an integer number (16606565551).
Almost surely, 233213131101 is an apocalyptic number.
It is an amenable number.
33213131101 is a deficient number, since it is larger than the sum of its proper divisors (1).
33213131101 is an equidigital number, since it uses as much as digits as its factorization.
33213131101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 33213131101 its reverse (10113131233), we get a palindrome (43326262334).
The spelling of 33213131101 in words is "thirty-three billion, two hundred thirteen million, one hundred thirty-one thousand, one hundred one".
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