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332132101203000 = 2335372731071392081
BaseRepresentation
bin100101110000100101000011…
…1111010010010010000111000
31121112222112000012012121120110
41023201022013322102100320
5322013123020401444000
63134215214135424320
7126646516042316100
oct11341120772222070
91545875005177513
10332132101203000
119691148451039a
12313015148250a0
1311342bcc39c527
145c033cac1c200
15285e7b8b7c850
hex12e1287e92438

332132101203000 has 1536 divisors, whose sum is σ = 1242839193523200. Its totient is φ = 73607159808000.

The previous prime is 332132101202897. The next prime is 332132101203103. The reversal of 332132101203000 is 302101231233.

It is an interprime number because it is at equal distance from previous prime (332132101202897) and next prime (332132101203103).

It is a super-2 number, since 2×3321321012030002 (a number of 30 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 159602161960 + ... + 159602164040.

It is an arithmetic number, because the mean of its divisors is an integer number (809140099950).

Almost surely, 2332132101203000 is an apocalyptic number.

332132101203000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 332132101203000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (621419596761600).

332132101203000 is an abundant number, since it is smaller than the sum of its proper divisors (910707092320200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

332132101203000 is a wasteful number, since it uses less digits than its factorization.

332132101203000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2438 (or 2417 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 332132101203000 its reverse (302101231233), we get a palindrome (332434202434233).

The spelling of 332132101203000 in words is "three hundred thirty-two trillion, one hundred thirty-two billion, one hundred one million, two hundred three thousand".