Base | Representation |
---|---|
bin | 110000010101100101100… |
… | …011000111001011001111 |
3 | 102202112220220211111000010 |
4 | 300111211203013023033 |
5 | 413410332114014210 |
6 | 11021550222404303 |
7 | 461662104143016 |
oct | 60254543071317 |
9 | 12675826744003 |
10 | 3321713423055 |
11 | 10708046a3105 |
12 | 45792b130693 |
13 | 1b130c002621 |
14 | b6ab3adba7d |
15 | 5b6132c4920 |
hex | 305658c72cf |
3321713423055 has 32 divisors (see below), whose sum is σ = 5488906272768. Its totient is φ = 1713582259200.
The previous prime is 3321713423027. The next prime is 3321713423087. The reversal of 3321713423055 is 5503243171233.
3321713423055 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3321713423055 - 25 = 3321713423023 is a prime.
It is a super-2 number, since 2×33217134230552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 832911 + ... + 2708720.
It is an arithmetic number, because the mean of its divisors is an integer number (171528321024).
Almost surely, 23321713423055 is an apocalyptic number.
3321713423055 is a deficient number, since it is larger than the sum of its proper divisors (2167192849713).
3321713423055 is a wasteful number, since it uses less digits than its factorization.
3321713423055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3543687.
The product of its (nonzero) digits is 226800, while the sum is 39.
Adding to 3321713423055 its reverse (5503243171233), we get a palindrome (8824956594288).
The spelling of 3321713423055 in words is "three trillion, three hundred twenty-one billion, seven hundred thirteen million, four hundred twenty-three thousand, fifty-five".
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