Base | Representation |
---|---|
bin | 110000010110110010110… |
… | …101001010010100000011 |
3 | 102202200021021120102101022 |
4 | 300112302311022110003 |
5 | 413421011030001011 |
6 | 11022323020500055 |
7 | 462036166646063 |
oct | 60266265122403 |
9 | 12680237512338 |
10 | 3323010000131 |
11 | 107130a572708 |
12 | 4580313aa62b |
13 | 1b148780c5b3 |
14 | b6b97dab3a3 |
15 | 5b68c03a8db |
hex | 305b2d4a503 |
3323010000131 has 2 divisors, whose sum is σ = 3323010000132. Its totient is φ = 3323010000130.
The previous prime is 3323010000077. The next prime is 3323010000161. The reversal of 3323010000131 is 1310000103233.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3323010000131 - 26 = 3323010000067 is a prime.
It is a super-2 number, since 2×33230100001312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3323010000161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1661505000065 + 1661505000066.
It is an arithmetic number, because the mean of its divisors is an integer number (1661505000066).
Almost surely, 23323010000131 is an apocalyptic number.
3323010000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3323010000131 is an equidigital number, since it uses as much as digits as its factorization.
3323010000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 3323010000131 its reverse (1310000103233), we get a palindrome (4633010103364).
The spelling of 3323010000131 in words is "three trillion, three hundred twenty-three billion, ten million, one hundred thirty-one", and thus it is an aban number.
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