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332324000423197 is a prime number
BaseRepresentation
bin100101110001111110011010…
…1111111101101110100011101
31121120122212022222110001021021
41023203330311333231310131
5322024244023102020242
63134443312130004141
7126666421346632216
oct11343746577556435
91546585288401237
10332324000423197
11969858a962a852
123133274b416651
1311358032320b73
145c0c7d30c040d
15286479ad4ab67
hex12e3f35fedd1d

332324000423197 has 2 divisors, whose sum is σ = 332324000423198. Its totient is φ = 332324000423196.

The previous prime is 332324000423183. The next prime is 332324000423243. The reversal of 332324000423197 is 791324000423233.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 328836914767321 + 3487085655876 = 18133861^2 + 1867374^2 .

It is a cyclic number.

It is not a de Polignac number, because 332324000423197 - 239 = 331774244609309 is a prime.

It is a super-3 number, since 3×3323240004231973 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (332324000421197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166162000211598 + 166162000211599.

It is an arithmetic number, because the mean of its divisors is an integer number (166162000211599).

Almost surely, 2332324000423197 is an apocalyptic number.

It is an amenable number.

332324000423197 is a deficient number, since it is larger than the sum of its proper divisors (1).

332324000423197 is an equidigital number, since it uses as much as digits as its factorization.

332324000423197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 653184, while the sum is 43.

The spelling of 332324000423197 in words is "three hundred thirty-two trillion, three hundred twenty-four billion, four hundred twenty-three thousand, one hundred ninety-seven".