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3323301101993 is a prime number
BaseRepresentation
bin110000010111000100001…
…011101000000110101001
3102202201000120022221001202
4300113010023220012221
5413422110040230433
611022411540053545
7462046333165415
oct60270413500651
912681016287052
103323301101993
111071449919864
124580b29942b5
131b1502c13212
14b6bc4905d45
155b6a788cee8
hex305c42e81a9

3323301101993 has 2 divisors, whose sum is σ = 3323301101994. Its totient is φ = 3323301101992.

The previous prime is 3323301101951. The next prime is 3323301102013. The reversal of 3323301101993 is 3991011033233.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3187396067584 + 135905034409 = 1785328^2 + 368653^2 .

It is a cyclic number.

It is not a de Polignac number, because 3323301101993 - 214 = 3323301085609 is a prime.

It is a super-3 number, since 3×33233011019933 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (3323301101933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1661650550996 + 1661650550997.

It is an arithmetic number, because the mean of its divisors is an integer number (1661650550997).

Almost surely, 23323301101993 is an apocalyptic number.

It is an amenable number.

3323301101993 is a deficient number, since it is larger than the sum of its proper divisors (1).

3323301101993 is an equidigital number, since it uses as much as digits as its factorization.

3323301101993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 39366, while the sum is 38.

The spelling of 3323301101993 in words is "three trillion, three hundred twenty-three billion, three hundred one million, one hundred one thousand, nine hundred ninety-three".