33240040121 has 2 divisors, whose sum is σ = 33240040122. Its totient is φ = 33240040120.

The previous prime is 33240040069. The next prime is 33240040123. The reversal of 33240040121 is 12104004233.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17479748521 + 15760291600 = 132211^2 + 125540^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-33240040121 is a prime.

It is a super-2 number, since 2×33240040121² (a number of 22 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 33240040123, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 33240040093 and 33240040102.

It is not a weakly prime, because it can be changed into another prime (33240040123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16620020060 + 16620020061.

It is an arithmetic number, because the mean of its divisors is an integer number (16620020061).

Almost surely, 2^33240040121 is an apocalyptic number.

It is an amenable number.

33240040121 is a deficient number, since it is larger than the sum of its proper divisors (1).

33240040121 is an equidigital number, since it uses as much as digits as its factorization.

33240040121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 33240040121 its reverse (12104004233), we get a palindrome (45344044354).

The spelling of 33240040121 in words is "thirty-three billion, two hundred forty million, forty thousand, one hundred twenty-one".