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33242423141131 is a prime number
BaseRepresentation
bin1111000111011110110101…
…10100101010001100001011
311100200221111121212120122221
413203233122310222030023
513324120440311004011
6154411205223554511
710000454143345441
oct743573264521413
9140627447776587
1033242423141131
11a65703a264846
12388a7302bba37
13157199336c599
1482cd28696b91
153c9aa2071971
hex1e3bdad2a30b

33242423141131 has 2 divisors, whose sum is σ = 33242423141132. Its totient is φ = 33242423141130.

The previous prime is 33242423141099. The next prime is 33242423141153. The reversal of 33242423141131 is 13114132424233.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 33242423141131 - 25 = 33242423141099 is a prime.

It is a super-3 number, since 3×332424231411313 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (33242423141531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16621211570565 + 16621211570566.

It is an arithmetic number, because the mean of its divisors is an integer number (16621211570566).

Almost surely, 233242423141131 is an apocalyptic number.

33242423141131 is a deficient number, since it is larger than the sum of its proper divisors (1).

33242423141131 is an equidigital number, since it uses as much as digits as its factorization.

33242423141131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 34.

Adding to 33242423141131 its reverse (13114132424233), we get a palindrome (46356555565364).

The spelling of 33242423141131 in words is "thirty-three trillion, two hundred forty-two billion, four hundred twenty-three million, one hundred forty-one thousand, one hundred thirty-one".