Base | Representation |
---|---|
bin | 11110111110001011… |
… | …000011100000001010 |
3 | 10011211121210022101211 |
4 | 132332023003200022 |
5 | 1021101331340132 |
6 | 23135521203334 |
7 | 2255045504101 |
oct | 367613034012 |
9 | 104747708354 |
10 | 33255340042 |
11 | 13115855201 |
12 | 654119054a |
13 | 319c93b802 |
14 | 187691b038 |
15 | ce9809147 |
hex | 7be2c380a |
33255340042 has 4 divisors (see below), whose sum is σ = 49883010066. Its totient is φ = 16627670020.
The previous prime is 33255340031. The next prime is 33255340051. The reversal of 33255340042 is 24004355233.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24004355233 = 7151 ⋅3356783.
It can be written as a sum of positive squares in only one way, i.e., 17394708321 + 15860631721 = 131889^2 + 125939^2 .
It is a super-3 number, since 3×332553400423 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 33255339986 and 33255340013.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8313835009 + ... + 8313835012.
Almost surely, 233255340042 is an apocalyptic number.
33255340042 is a deficient number, since it is larger than the sum of its proper divisors (16627670024).
33255340042 is a wasteful number, since it uses less digits than its factorization.
33255340042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16627670023.
The product of its (nonzero) digits is 43200, while the sum is 31.
Adding to 33255340042 its reverse (24004355233), we get a palindrome (57259695275).
The spelling of 33255340042 in words is "thirty-three billion, two hundred fifty-five million, three hundred forty thousand, forty-two".
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