33303122130433 has 2 divisors, whose sum is σ = 33303122130434. Its totient is φ = 33303122130432.

The previous prime is 33303122130359. The next prime is 33303122130497. The reversal of 33303122130433 is 33403122130333.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19670360376384 + 13632761754049 = 4435128^2 + 3692257^2 .

It is a cyclic number.

It is not a de Polignac number, because 33303122130433 - 2³⁷ = 33165683176961 is a prime.

It is a super-2 number, since 2×33303122130433² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33303122130395 and 33303122130404.

It is not a weakly prime, because it can be changed into another prime (33303122430433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16651561065216 + 16651561065217.

It is an arithmetic number, because the mean of its divisors is an integer number (16651561065217).

Almost surely, 2^{33303122130433} is an apocalyptic number.

It is an amenable number.

33303122130433 is a deficient number, since it is larger than the sum of its proper divisors (1).

33303122130433 is an equidigital number, since it uses as much as digits as its factorization.

33303122130433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34992, while the sum is 31.

Adding to 33303122130433 its reverse (33403122130333), we get a palindrome (66706244260766).

The spelling of 33303122130433 in words is "thirty-three trillion, three hundred three billion, one hundred twenty-two million, one hundred thirty thousand, four hundred thirty-three".