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3331102431132 = 2234722337246557
BaseRepresentation
bin110000011110010101001…
…011010101011110011100
3102210110011020220111210000
4300132111023111132130
5414034044210244012
611030142021414300
7462443552325300
oct60362513253634
912713136814700
103331102431132
111074792531913
1245970b56a390
131b2177245cc8
14b7324a55d00
155b9b26e2ddc
hex307952d579c

3331102431132 has 360 divisors, whose sum is σ = 10856059197984. Its totient is φ = 885755388672.

The previous prime is 3331102431121. The next prime is 3331102431179. The reversal of 3331102431132 is 2311342011333.

3331102431132 is a `hidden beast` number, since 3 + 3 + 311 + 0 + 2 + 4 + 311 + 32 = 666.

It is a super-3 number, since 3×33311024311323 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 3331102431096 and 3331102431105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 13387198 + ... + 13633754.

Almost surely, 23331102431132 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3331102431132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5428029598992).

3331102431132 is an abundant number, since it is smaller than the sum of its proper divisors (7524956766852).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3331102431132 is a wasteful number, since it uses less digits than its factorization.

3331102431132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 246647 (or 246629 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 3331102431132 its reverse (2311342011333), we get a palindrome (5642444442465).

The spelling of 3331102431132 in words is "three trillion, three hundred thirty-one billion, one hundred two million, four hundred thirty-one thousand, one hundred thirty-two".