Base | Representation |
---|---|
bin | 110000011110010111011… |
… | …001011000111110010111 |
3 | 102210110020211222102210001 |
4 | 300132113121120332113 |
5 | 414034133223414121 |
6 | 11030145431512131 |
7 | 462444514003204 |
oct | 60362731307627 |
9 | 12713224872701 |
10 | 3331139669911 |
11 | 1074801556969 |
12 | 45971bb28647 |
13 | 1b2181b83aa1 |
14 | b732998acab |
15 | 5b9b5aeb991 |
hex | 30797658f97 |
3331139669911 has 2 divisors, whose sum is σ = 3331139669912. Its totient is φ = 3331139669910.
The previous prime is 3331139669863. The next prime is 3331139669951. The reversal of 3331139669911 is 1199669311333.
3331139669911 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3331139669911 - 29 = 3331139669399 is a prime.
It is a super-2 number, since 2×33311396699112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3331139669951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665569834955 + 1665569834956.
It is an arithmetic number, because the mean of its divisors is an integer number (1665569834956).
Almost surely, 23331139669911 is an apocalyptic number.
3331139669911 is a deficient number, since it is larger than the sum of its proper divisors (1).
3331139669911 is an equidigital number, since it uses as much as digits as its factorization.
3331139669911 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2125764, while the sum is 55.
The spelling of 3331139669911 in words is "three trillion, three hundred thirty-one billion, one hundred thirty-nine million, six hundred sixty-nine thousand, nine hundred eleven".
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