Base | Representation |
---|---|
bin | 110000011110011011001… |
… | …110110010101010101111 |
3 | 102210110102100000202122220 |
4 | 300132123032302222233 |
5 | 414034301211003211 |
6 | 11030200050410423 |
7 | 462446224544556 |
oct | 60363316625257 |
9 | 12713370022586 |
10 | 3331204000431 |
11 | 10748348a538a |
12 | 459739590a13 |
13 | 1b21922b8b98 |
14 | b7334334d9d |
15 | 5b9bb5a7806 |
hex | 3079b3b2aaf |
3331204000431 has 32 divisors (see below), whose sum is σ = 4586100277248. Its totient is φ = 2149981294560.
The previous prime is 3331204000429. The next prime is 3331204000459. The reversal of 3331204000431 is 1340004021333.
It is not a de Polignac number, because 3331204000431 - 21 = 3331204000429 is a prime.
It is a super-2 number, since 2×33312040004312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3331204000471) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2663740 + ... + 3709166.
It is an arithmetic number, because the mean of its divisors is an integer number (143315633664).
Almost surely, 23331204000431 is an apocalyptic number.
3331204000431 is a deficient number, since it is larger than the sum of its proper divisors (1254896276817).
3331204000431 is a wasteful number, since it uses less digits than its factorization.
3331204000431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1045771.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 3331204000431 its reverse (1340004021333), we get a palindrome (4671208021764).
The spelling of 3331204000431 in words is "three trillion, three hundred thirty-one billion, two hundred four million, four hundred thirty-one", and thus it is an aban number.
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