Base | Representation |
---|---|
bin | 110000011110011011101… |
… | …001111100111000000101 |
3 | 102210110102211102111001120 |
4 | 300132123221330320011 |
5 | 414034310021321013 |
6 | 11030200503144153 |
7 | 462446342216661 |
oct | 60363351747005 |
9 | 12713384374046 |
10 | 3331211120133 |
11 | 1074838918536 |
12 | 45973ba45059 |
13 | 1b219390c720 |
14 | b73352698a1 |
15 | 5b9bc012123 |
hex | 3079ba7ce05 |
3331211120133 has 16 divisors (see below), whose sum is σ = 4784290961856. Its totient is φ = 2049541735680.
The previous prime is 3331211120123. The next prime is 3331211120173. The reversal of 3331211120133 is 3310211121333.
It is not a de Polignac number, because 3331211120133 - 213 = 3331211111941 is a prime.
It is a super-2 number, since 2×33312111201332 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3331211120123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8862235 + ... + 9230472.
It is an arithmetic number, because the mean of its divisors is an integer number (299018185116).
Almost surely, 23331211120133 is an apocalyptic number.
It is an amenable number.
3331211120133 is a deficient number, since it is larger than the sum of its proper divisors (1453079841723).
3331211120133 is a wasteful number, since it uses less digits than its factorization.
3331211120133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18097444.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 3331211120133 its reverse (3310211121333), we get a palindrome (6641422241466).
The spelling of 3331211120133 in words is "three trillion, three hundred thirty-one billion, two hundred eleven million, one hundred twenty thousand, one hundred thirty-three".
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