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333130021230000 = 2435471156399071
BaseRepresentation
bin100101110111110101110000…
…0100101000101010110110000
31121200111220210221210110111110
41023233223200211011112300
5322131000240413330000
63140301452525113320
7130111564322511651
oct11357534045052660
91550456727713443
10333130021230000
1197166715336835
12314429b60b8840
13113b604576c9c7
145c39816d0d528
15287a7229d5850
hex12efae09455b0

333130021230000 has 200 divisors, whose sum is σ = 1090534444471296. Its totient is φ = 87583479200000.

The previous prime is 333130021229977. The next prime is 333130021230001. The reversal of 333130021230000 is 32120031333.

It is a tau number, because it is divible by the number of its divisors (200).

It is a super-2 number, since 2×3331300212300002 (a number of 30 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (333130021230001) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 76069536 + ... + 80329535.

Almost surely, 2333130021230000 is an apocalyptic number.

333130021230000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

333130021230000 is an abundant number, since it is smaller than the sum of its proper divisors (757404423241296).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

333130021230000 is a wasteful number, since it uses less digits than its factorization.

333130021230000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156399173 (or 156399152 counting only the distinct ones).

The product of its (nonzero) digits is 972, while the sum is 21.

Adding to 333130021230000 its reverse (32120031333), we get a palindrome (333162141261333).

The spelling of 333130021230000 in words is "three hundred thirty-three trillion, one hundred thirty billion, twenty-one million, two hundred thirty thousand".