Base | Representation |
---|---|
bin | 11111000001101010… |
… | …111010101010110001 |
3 | 10011222201012202210221 |
4 | 133001222322222301 |
5 | 1021211342232423 |
6 | 23145415053041 |
7 | 2256360350506 |
oct | 370152725261 |
9 | 104881182727 |
10 | 33314024113 |
11 | 13145997437 |
12 | 6558971181 |
13 | 31abb47806 |
14 | 18806354ad |
15 | ceea4be5d |
hex | 7c1abaab1 |
33314024113 has 8 divisors (see below), whose sum is σ = 34881110208. Its totient is φ = 31756825584.
The previous prime is 33314024111. The next prime is 33314024119. The reversal of 33314024113 is 31142041333.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 33314024113 - 21 = 33314024111 is a prime.
It is a super-2 number, since 2×333140241132 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (33314024111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2464995 + ... + 2478472.
It is an arithmetic number, because the mean of its divisors is an integer number (4360138776).
Almost surely, 233314024113 is an apocalyptic number.
It is an amenable number.
33314024113 is a deficient number, since it is larger than the sum of its proper divisors (1567086095).
33314024113 is a wasteful number, since it uses less digits than its factorization.
33314024113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4943783.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 33314024113 its reverse (31142041333), we get a palindrome (64456065446).
The spelling of 33314024113 in words is "thirty-three billion, three hundred fourteen million, twenty-four thousand, one hundred thirteen".
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