33325141224145 has 8 divisors (see below), whose sum is σ = 39992509135656. Its totient is φ = 26658553201536.

The previous prime is 33325141223993. The next prime is 33325141224211. The reversal of 33325141224145 is 54142214152333.

It can be written as a sum of positive squares in 4 ways, for example, as 5804803587856 + 27520337636289 = 2409316^2 + 5245983^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 33325141224145 - 2¹³ = 33325141215953 is a prime.

It is a super-2 number, since 2×33325141224145² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 33325141224098 and 33325141224107.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 194878212 + ... + 195049141.

It is an arithmetic number, because the mean of its divisors is an integer number (4999063641957).

Almost surely, 2^{33325141224145} is an apocalyptic number.

It is an amenable number.

33325141224145 is a deficient number, since it is larger than the sum of its proper divisors (6667367911511).

33325141224145 is a wasteful number, since it uses less digits than its factorization.

33325141224145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 389944451.

The product of its digits is 345600, while the sum is 40.

Adding to 33325141224145 its reverse (54142214152333), we get a palindrome (87467355376478).

The spelling of 33325141224145 in words is "thirty-three trillion, three hundred twenty-five billion, one hundred forty-one million, two hundred twenty-four thousand, one hundred forty-five".