Base | Representation |
---|---|
bin | 110000100000001111001… |
… | …110001100101111010011 |
3 | 102210122102221202220010221 |
4 | 300200033032030233103 |
5 | 414102242400032011 |
6 | 11031121124133511 |
7 | 462545364360115 |
oct | 60401716145723 |
9 | 12718387686127 |
10 | 3333150002131 |
11 | 1075643310254 |
12 | 459ba1237297 |
13 | 1b2412507c91 |
14 | b747a9753b5 |
15 | 5ba82350971 |
hex | 3080f38cbd3 |
3333150002131 has 2 divisors, whose sum is σ = 3333150002132. Its totient is φ = 3333150002130.
The previous prime is 3333150002129. The next prime is 3333150002173. The reversal of 3333150002131 is 1312000513333.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3333150002131 - 21 = 3333150002129 is a prime.
It is a super-2 number, since 2×33331500021312 (a number of 26 digits) contains 22 as substring.
Together with 3333150002129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 3333150002096 and 3333150002105.
It is not a weakly prime, because it can be changed into another prime (3333150032131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1666575001065 + 1666575001066.
It is an arithmetic number, because the mean of its divisors is an integer number (1666575001066).
Almost surely, 23333150002131 is an apocalyptic number.
3333150002131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3333150002131 is an equidigital number, since it uses as much as digits as its factorization.
3333150002131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2430, while the sum is 25.
Adding to 3333150002131 its reverse (1312000513333), we get a palindrome (4645150515464).
The spelling of 3333150002131 in words is "three trillion, three hundred thirty-three billion, one hundred fifty million, two thousand, one hundred thirty-one".
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