Base | Representation |
---|---|
bin | 110000100001000010000… |
… | …001110110111010100111 |
3 | 102210201122100201110002201 |
4 | 300201002001312322213 |
5 | 414111014103430111 |
6 | 11031341454115331 |
7 | 462605454566554 |
oct | 60410201667247 |
9 | 12721570643081 |
10 | 3334002405031 |
11 | 1075a40493161 |
12 | 45a19a7abb47 |
13 | 1b2519ca7bac |
14 | b751bc61a2b |
15 | 5bad20c96c1 |
hex | 30842076ea7 |
3334002405031 has 4 divisors (see below), whose sum is σ = 3376204967200. Its totient is φ = 3291799842864.
The previous prime is 3334002405011. The next prime is 3334002405059. The reversal of 3334002405031 is 1305042004333.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3334002405031 - 221 = 3334000307879 is a prime.
It is a super-2 number, since 2×33340024050312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3334002405011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21101280966 + ... + 21101281123.
It is an arithmetic number, because the mean of its divisors is an integer number (844051241800).
Almost surely, 23334002405031 is an apocalyptic number.
3334002405031 is a deficient number, since it is larger than the sum of its proper divisors (42202562169).
3334002405031 is an equidigital number, since it uses as much as digits as its factorization.
3334002405031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42202562168.
The product of its (nonzero) digits is 12960, while the sum is 28.
Adding to 3334002405031 its reverse (1305042004333), we get a palindrome (4639044409364).
The spelling of 3334002405031 in words is "three trillion, three hundred thirty-four billion, two million, four hundred five thousand, thirty-one".
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