Search a number
-
+
33341397949 is a prime number
BaseRepresentation
bin11111000011010011…
…010101101110111101
310012001121201111122201
4133003103111232331
51021240344213244
623152233511501
72260142130556
oct370323255675
9105047644581
1033341397949
111315a393842
126565b72591
1331b4710352
14188411d32d
15d02157ad4
hex7c34d5bbd

33341397949 has 2 divisors, whose sum is σ = 33341397950. Its totient is φ = 33341397948.

The previous prime is 33341397937. The next prime is 33341397953. The reversal of 33341397949 is 94979314333.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33326328025 + 15069924 = 182555^2 + 3882^2 .

It is a cyclic number.

It is not a de Polignac number, because 33341397949 - 219 = 33340873661 is a prime.

It is a super-3 number, since 3×333413979493 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 33341397949.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33344397949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16670698974 + 16670698975.

It is an arithmetic number, because the mean of its divisors is an integer number (16670698975).

Almost surely, 233341397949 is an apocalyptic number.

It is an amenable number.

33341397949 is a deficient number, since it is larger than the sum of its proper divisors (1).

33341397949 is an equidigital number, since it uses as much as digits as its factorization.

33341397949 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6613488, while the sum is 55.

The spelling of 33341397949 in words is "thirty-three billion, three hundred forty-one million, three hundred ninety-seven thousand, nine hundred forty-nine".