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3334978505317 is a prime number
BaseRepresentation
bin110000100001111100001…
…101011000101001100101
3102210211011101102110222011
4300201330031120221211
5414120013444132232
611032022403234221
7462641606400154
oct60417415305145
912724141373864
103334978505317
1110763a1472808
1245a411678971
131b2644297924
14b75b174b59b
155bb3cb39547
hex3087c358a65

3334978505317 has 2 divisors, whose sum is σ = 3334978505318. Its totient is φ = 3334978505316.

The previous prime is 3334978505293. The next prime is 3334978505347. The reversal of 3334978505317 is 7135058794333.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3334663123236 + 315382081 = 1826106^2 + 17759^2 .

It is a cyclic number.

It is not a de Polignac number, because 3334978505317 - 219 = 3334977981029 is a prime.

It is a super-2 number, since 2×33349785053172 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3334978505347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1667489252658 + 1667489252659.

It is an arithmetic number, because the mean of its divisors is an integer number (1667489252659).

Almost surely, 23334978505317 is an apocalyptic number.

It is an amenable number.

3334978505317 is a deficient number, since it is larger than the sum of its proper divisors (1).

3334978505317 is an equidigital number, since it uses as much as digits as its factorization.

3334978505317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28576800, while the sum is 58.

The spelling of 3334978505317 in words is "three trillion, three hundred thirty-four billion, nine hundred seventy-eight million, five hundred five thousand, three hundred seventeen".