33400400214031 has 2 divisors, whose sum is σ = 33400400214032. Its totient is φ = 33400400214030.

The previous prime is 33400400214023. The next prime is 33400400214037. The reversal of 33400400214031 is 13041200400433.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 33400400214031 - 2³ = 33400400214023 is a prime.

It is a super-2 number, since 2×33400400214031² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33400400213987 and 33400400214005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33400400214037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16700200107015 + 16700200107016.

It is an arithmetic number, because the mean of its divisors is an integer number (16700200107016).

Almost surely, 2^{33400400214031} is an apocalyptic number.

33400400214031 is a deficient number, since it is larger than the sum of its proper divisors (1).

33400400214031 is an equidigital number, since it uses as much as digits as its factorization.

33400400214031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 33400400214031 its reverse (13041200400433), we get a palindrome (46441600614464).

The spelling of 33400400214031 in words is "thirty-three trillion, four hundred billion, four hundred million, two hundred fourteen thousand, thirty-one".