3340104113 has 4 divisors (see below), whose sum is σ = 3370747380. Its totient is φ = 3309460848.

The previous prime is 3340104101. The next prime is 3340104133. The reversal of 3340104113 is 3114010433.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3114010433 = 103 ⋅30233111.

It can be written as a sum of positive squares in 2 ways, for example, as 2005517089 + 1334587024 = 44783^2 + 36532^2 .

It is a cyclic number.

It is not a de Polignac number, because 3340104113 - 2²⁰ = 3339055537 is a prime.

It is a super-2 number, since 2×3340104113² = 22312590971359033538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3340104133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15321470 + ... + 15321687.

It is an arithmetic number, because the mean of its divisors is an integer number (842686845).

Almost surely, 2^3340104113 is an apocalyptic number.

It is an amenable number.

3340104113 is a deficient number, since it is larger than the sum of its proper divisors (30643267).

3340104113 is a wasteful number, since it uses less digits than its factorization.

3340104113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30643266.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 3340104113 is about 57793.6338449141. The cubic root of 3340104113 is about 1494.8123182850.

Adding to 3340104113 its reverse (3114010433), we get a palindrome (6454114546).

The spelling of 3340104113 in words is "three billion, three hundred forty million, one hundred four thousand, one hundred thirteen".