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33401220132112 = 247298225179751
BaseRepresentation
bin1111001100000110100111…
…10111000110110100010000
311101021010101110102112112021
413212003103313012310100
513334221144323211422
6155012150402341224
710015105241451640
oct746032367066420
9141233343375467
1033401220132112
11a708417aa6478
1238b546905a814
13158394c300241
148368b04d6520
153cdc980cbdc7
hex1e60d3dc6d10

33401220132112 has 20 divisors (see below), whose sum is σ = 73959844578496. Its totient is φ = 14314808628000.

The previous prime is 33401220132043. The next prime is 33401220132113. The reversal of 33401220132112 is 21123102210433.

It is a super-2 number, since 2×334012201321122 (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (33401220132113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149112589764 + ... + 149112589987.

Almost surely, 233401220132112 is an apocalyptic number.

It is an amenable number.

33401220132112 is an abundant number, since it is smaller than the sum of its proper divisors (40558624446384).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

33401220132112 is a wasteful number, since it uses less digits than its factorization.

33401220132112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 298225179766 (or 298225179760 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 33401220132112 its reverse (21123102210433), we get a palindrome (54524322342545).

The spelling of 33401220132112 in words is "thirty-three trillion, four hundred one billion, two hundred twenty million, one hundred thirty-two thousand, one hundred twelve".

Divisors: 1 2 4 7 8 14 16 28 56 112 298225179751 596450359502 1192900719004 2087576258257 2385801438008 4175152516514 4771602876016 8350305033028 16700610066056 33401220132112