Base | Representation |
---|---|
bin | 1111001100000110100111… |
… | …10111000110110100010000 |
3 | 11101021010101110102112112021 |
4 | 13212003103313012310100 |
5 | 13334221144323211422 |
6 | 155012150402341224 |
7 | 10015105241451640 |
oct | 746032367066420 |
9 | 141233343375467 |
10 | 33401220132112 |
11 | a708417aa6478 |
12 | 38b546905a814 |
13 | 158394c300241 |
14 | 8368b04d6520 |
15 | 3cdc980cbdc7 |
hex | 1e60d3dc6d10 |
33401220132112 has 20 divisors (see below), whose sum is σ = 73959844578496. Its totient is φ = 14314808628000.
The previous prime is 33401220132043. The next prime is 33401220132113. The reversal of 33401220132112 is 21123102210433.
It is a super-2 number, since 2×334012201321122 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (33401220132113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149112589764 + ... + 149112589987.
Almost surely, 233401220132112 is an apocalyptic number.
It is an amenable number.
33401220132112 is an abundant number, since it is smaller than the sum of its proper divisors (40558624446384).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
33401220132112 is a wasteful number, since it uses less digits than its factorization.
33401220132112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 298225179766 (or 298225179760 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 33401220132112 its reverse (21123102210433), we get a palindrome (54524322342545).
The spelling of 33401220132112 in words is "thirty-three trillion, four hundred one billion, two hundred twenty million, one hundred thirty-two thousand, one hundred twelve".
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