Base | Representation |
---|---|
bin | 110000100110101110111… |
… | …001111101111010111010 |
3 | 102211022102222121201201020 |
4 | 300212232321331322322 |
5 | 414211033222123120 |
6 | 11034233133403310 |
7 | 463213246504662 |
oct | 60465671757272 |
9 | 12738388551636 |
10 | 3340124020410 |
11 | 10785a1a29421 |
12 | 45b408939536 |
13 | 1b2c84314c08 |
14 | b793cc8b1a2 |
15 | 5bd3e736640 |
hex | 309aee7deba |
3340124020410 has 32 divisors (see below), whose sum is σ = 8016427224000. Its totient is φ = 890685341568.
The previous prime is 3340124020397. The next prime is 3340124020517. The reversal of 3340124020410 is 140204210433.
It is a super-2 number, since 2×33401240204102 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1056841 + ... + 2792339.
It is an arithmetic number, because the mean of its divisors is an integer number (250513350750).
Almost surely, 23340124020410 is an apocalyptic number.
3340124020410 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
3340124020410 is an abundant number, since it is smaller than the sum of its proper divisors (4676303203590).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3340124020410 is a wasteful number, since it uses less digits than its factorization.
3340124020410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1799662.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 3340124020410 its reverse (140204210433), we get a palindrome (3480328230843).
The spelling of 3340124020410 in words is "three trillion, three hundred forty billion, one hundred twenty-four million, twenty thousand, four hundred ten".
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