Base | Representation |
---|---|
bin | 110000100110101111100… |
… | …000100010100100011001 |
3 | 102211022110200122110012022 |
4 | 300212233200202210121 |
5 | 414211043314210433 |
6 | 11034234134224225 |
7 | 463213431450551 |
oct | 60465740424431 |
9 | 12738420573168 |
10 | 3340134131993 |
11 | 10785a77053aa |
12 | 45b4101b5075 |
13 | 1b2c864454b9 |
14 | b7940360161 |
15 | 5bd40582698 |
hex | 309af822919 |
3340134131993 has 2 divisors, whose sum is σ = 3340134131994. Its totient is φ = 3340134131992.
The previous prime is 3340134131849. The next prime is 3340134132019. The reversal of 3340134131993 is 3991314310433.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3055178880649 + 284955251344 = 1747907^2 + 533812^2 .
It is a cyclic number.
It is not a de Polignac number, because 3340134131993 - 216 = 3340134066457 is a prime.
It is a super-2 number, since 2×33401341319932 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3340134131293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670067065996 + 1670067065997.
It is an arithmetic number, because the mean of its divisors is an integer number (1670067065997).
Almost surely, 23340134131993 is an apocalyptic number.
It is an amenable number.
3340134131993 is a deficient number, since it is larger than the sum of its proper divisors (1).
3340134131993 is an equidigital number, since it uses as much as digits as its factorization.
3340134131993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 314928, while the sum is 44.
The spelling of 3340134131993 in words is "three trillion, three hundred forty billion, one hundred thirty-four million, one hundred thirty-one thousand, nine hundred ninety-three".
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