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3340134131993 is a prime number
BaseRepresentation
bin110000100110101111100…
…000100010100100011001
3102211022110200122110012022
4300212233200202210121
5414211043314210433
611034234134224225
7463213431450551
oct60465740424431
912738420573168
103340134131993
1110785a77053aa
1245b4101b5075
131b2c864454b9
14b7940360161
155bd40582698
hex309af822919

3340134131993 has 2 divisors, whose sum is σ = 3340134131994. Its totient is φ = 3340134131992.

The previous prime is 3340134131849. The next prime is 3340134132019. The reversal of 3340134131993 is 3991314310433.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3055178880649 + 284955251344 = 1747907^2 + 533812^2 .

It is a cyclic number.

It is not a de Polignac number, because 3340134131993 - 216 = 3340134066457 is a prime.

It is a super-2 number, since 2×33401341319932 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3340134131293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670067065996 + 1670067065997.

It is an arithmetic number, because the mean of its divisors is an integer number (1670067065997).

Almost surely, 23340134131993 is an apocalyptic number.

It is an amenable number.

3340134131993 is a deficient number, since it is larger than the sum of its proper divisors (1).

3340134131993 is an equidigital number, since it uses as much as digits as its factorization.

3340134131993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 314928, while the sum is 44.

The spelling of 3340134131993 in words is "three trillion, three hundred forty billion, one hundred thirty-four million, one hundred thirty-one thousand, nine hundred ninety-three".