3340134132019 has 2 divisors, whose sum is σ = 3340134132020. Its totient is φ = 3340134132018.

The previous prime is 3340134131993. The next prime is 3340134132037. The reversal of 3340134132019 is 9102314310433.

3340134132019 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3340134132019 - 2¹¹ = 3340134129971 is a prime.

It is a super-2 number, since 2×3340134132019² (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3340134136019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670067066009 + 1670067066010.

It is an arithmetic number, because the mean of its divisors is an integer number (1670067066010).

Almost surely, 2^{3340134132019} is an apocalyptic number.

3340134132019 is a deficient number, since it is larger than the sum of its proper divisors (1).

3340134132019 is an equidigital number, since it uses as much as digits as its factorization.

3340134132019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23328, while the sum is 34.

The spelling of 3340134132019 in words is "three trillion, three hundred forty billion, one hundred thirty-four million, one hundred thirty-two thousand, nineteen".