334014143241 has 4 divisors (see below), whose sum is σ = 445352190992. Its totient is φ = 222676095492.

The previous prime is 334014143237. The next prime is 334014143251. The reversal of 334014143241 is 142341410433.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 142341410433 = 3 ⋅47447136811.

It is not a de Polignac number, because 334014143241 - 2² = 334014143237 is a prime.

It is a super-2 number, since 2×334014143241² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 334014143199 and 334014143208.

It is not an unprimeable number, because it can be changed into a prime (334014143251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55669023871 + ... + 55669023876.

It is an arithmetic number, because the mean of its divisors is an integer number (111338047748).

Almost surely, 2^334014143241 is an apocalyptic number.

It is an amenable number.

334014143241 is a deficient number, since it is larger than the sum of its proper divisors (111338047751).

334014143241 is a wasteful number, since it uses less digits than its factorization.

334014143241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 111338047750.

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 334014143241 its reverse (142341410433), we get a palindrome (476355553674).

The spelling of 334014143241 in words is "three hundred thirty-four billion, fourteen million, one hundred forty-three thousand, two hundred forty-one".