Base | Representation |
---|---|
bin | 110000100110111010000… |
… | …100011011100001101101 |
3 | 102211022221001001011011001 |
4 | 300212322010123201231 |
5 | 414211424143444433 |
6 | 11034303504000301 |
7 | 463221012454021 |
oct | 60467204334155 |
9 | 12738831034131 |
10 | 3340311312493 |
11 | 1078688721771 |
12 | 45b45b600091 |
13 | 1b2cb406cc2c |
14 | b7959ac2381 |
15 | 5bd50dd057d |
hex | 309ba11b86d |
3340311312493 has 2 divisors, whose sum is σ = 3340311312494. Its totient is φ = 3340311312492.
The previous prime is 3340311312391. The next prime is 3340311312521. The reversal of 3340311312493 is 3942131130433.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2903387668489 + 436923644004 = 1703933^2 + 661002^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3340311312493 is a prime.
It is a super-2 number, since 2×33403113124932 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3340311312193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670155656246 + 1670155656247.
It is an arithmetic number, because the mean of its divisors is an integer number (1670155656247).
Almost surely, 23340311312493 is an apocalyptic number.
It is an amenable number.
3340311312493 is a deficient number, since it is larger than the sum of its proper divisors (1).
3340311312493 is an equidigital number, since it uses as much as digits as its factorization.
3340311312493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69984, while the sum is 37.
The spelling of 3340311312493 in words is "three trillion, three hundred forty billion, three hundred eleven million, three hundred twelve thousand, four hundred ninety-three".
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