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334031555101 is a prime number
BaseRepresentation
bin1001101110001011101…
…01010000101000011101
31011221012020022011000211
410313011311100220131
520433044034230401
6413241343252421
733063420241216
oct4670565205035
91157166264024
10334031555101
11119731117352
12548a25aa111
132566451316a
141224ab9640d
158a501e2951
hex4dc5d50a1d

334031555101 has 2 divisors, whose sum is σ = 334031555102. Its totient is φ = 334031555100.

The previous prime is 334031555089. The next prime is 334031555147. The reversal of 334031555101 is 101555130433.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 229152732601 + 104878822500 = 478699^2 + 323850^2 .

It is a cyclic number.

It is not a de Polignac number, because 334031555101 - 27 = 334031554973 is a prime.

It is a super-2 number, since 2×3340315551012 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (334031555201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167015777550 + 167015777551.

It is an arithmetic number, because the mean of its divisors is an integer number (167015777551).

Almost surely, 2334031555101 is an apocalyptic number.

It is an amenable number.

334031555101 is a deficient number, since it is larger than the sum of its proper divisors (1).

334031555101 is an equidigital number, since it uses as much as digits as its factorization.

334031555101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 334031555101 its reverse (101555130433), we get a palindrome (435586685534).

The spelling of 334031555101 in words is "three hundred thirty-four billion, thirty-one million, five hundred fifty-five thousand, one hundred one".