Base | Representation |
---|---|
bin | 100101111110011101100011… |
… | …0010111000011100111110111 |
3 | 1121210201220220220200022120012 |
4 | 1023330323012113003213313 |
5 | 322240403123242141043 |
6 | 3142235524324330435 |
7 | 130234413302102105 |
oct | 11374730627034767 |
9 | 1553656826608505 |
10 | 334040114412023 |
11 | 974876871a5678 |
12 | 3156b266543a1b |
13 | 11450b03310666 |
14 | 5c6b8b0992c75 |
15 | 289423b179a18 |
hex | 12fcec65c39f7 |
334040114412023 has 2 divisors, whose sum is σ = 334040114412024. Its totient is φ = 334040114412022.
The previous prime is 334040114411933. The next prime is 334040114412029. The reversal of 334040114412023 is 320214411040433.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 334040114412023 - 210 = 334040114410999 is a prime.
It is a super-2 number, since 2×3340401144120232 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (334040114412029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167020057206011 + 167020057206012.
It is an arithmetic number, because the mean of its divisors is an integer number (167020057206012).
Almost surely, 2334040114412023 is an apocalyptic number.
334040114412023 is a deficient number, since it is larger than the sum of its proper divisors (1).
334040114412023 is an equidigital number, since it uses as much as digits as its factorization.
334040114412023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 334040114412023 its reverse (320214411040433), we get a palindrome (654254525452456).
The spelling of 334040114412023 in words is "three hundred thirty-four trillion, forty billion, one hundred fourteen million, four hundred twelve thousand, twenty-three".
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