3340440440433 has 6 divisors (see below), whose sum is σ = 4825080636194. Its totient is φ = 2226960293616.

The previous prime is 3340440440419. The next prime is 3340440440437.

3340440440433 is nontrivially palindromic in base 10.

It can be written as a sum of positive squares in only one way, i.e., 3325619082384 + 14821358049 = 1823628^2 + 121743^2 .

It is not a de Polignac number, because 3340440440433 - 2¹⁴ = 3340440424049 is a prime.

It is a super-3 number, since 3×3340440440433³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3340440440437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 185580024460 + ... + 185580024477.

Almost surely, 2^{3340440440433} is an apocalyptic number.

It is an amenable number.

3340440440433 is a deficient number, since it is larger than the sum of its proper divisors (1484640195761).

3340440440433 is a wasteful number, since it uses less digits than its factorization.

3340440440433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 371160048943 (or 371160048940 counting only the distinct ones).

The product of its (nonzero) digits is 331776, while the sum is 36.

It can be divided in two parts, 3340440 and 440433, that added together give a palindrome (3780873).

The spelling of 3340440440433 in words is "three trillion, three hundred forty billion, four hundred forty million, four hundred forty thousand, four hundred thirty-three".