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334044050023 is a prime number
BaseRepresentation
bin1001101110001101001…
…00111011001001100111
31011221020002210221211201
410313012210323021213
520433110234100043
6413242511143331
733063631401445
oct4670644731147
91157202727751
10334044050023
11119738180a32
12548a6814b47
1325666c994c8
141224c6c9b95
158a5135ec4d
hex4dc693b267

334044050023 has 2 divisors, whose sum is σ = 334044050024. Its totient is φ = 334044050022.

The previous prime is 334044049993. The next prime is 334044050033. The reversal of 334044050023 is 320050440433.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 334044050023 - 217 = 334043918951 is a prime.

It is a super-2 number, since 2×3340440500232 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 334044049973 and 334044050000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (334044050033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167022025011 + 167022025012.

It is an arithmetic number, because the mean of its divisors is an integer number (167022025012).

Almost surely, 2334044050023 is an apocalyptic number.

334044050023 is a deficient number, since it is larger than the sum of its proper divisors (1).

334044050023 is an equidigital number, since it uses as much as digits as its factorization.

334044050023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 28.

Adding to 334044050023 its reverse (320050440433), we get a palindrome (654094490456).

The spelling of 334044050023 in words is "three hundred thirty-four billion, forty-four million, fifty thousand, twenty-three".