Base | Representation |
---|---|
bin | 100101111110011111011010… |
… | …0100101100111000000110111 |
3 | 1121210202022020110100101222202 |
4 | 1023330332310211213000313 |
5 | 322240434314432020112 |
6 | 3142241425101415115 |
7 | 130234614323216042 |
oct | 11374766445470067 |
9 | 1553668213311882 |
10 | 334044111204407 |
11 | 9748934829897a |
12 | 3156bba0b6a49b |
13 | 114512bc37b076 |
14 | 5c6bb6d70dc59 |
15 | 28943c1eb96c2 |
hex | 12fcfb4967037 |
334044111204407 has 2 divisors, whose sum is σ = 334044111204408. Its totient is φ = 334044111204406.
The previous prime is 334044111204299. The next prime is 334044111204413. The reversal of 334044111204407 is 704402111440433.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 334044111204407 - 212 = 334044111200311 is a prime.
It is a super-2 number, since 2×3340441112044072 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (334044111204007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167022055602203 + 167022055602204.
It is an arithmetic number, because the mean of its divisors is an integer number (167022055602204).
Almost surely, 2334044111204407 is an apocalyptic number.
334044111204407 is a deficient number, since it is larger than the sum of its proper divisors (1).
334044111204407 is an equidigital number, since it uses as much as digits as its factorization.
334044111204407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129024, while the sum is 38.
The spelling of 334044111204407 in words is "three hundred thirty-four trillion, forty-four billion, one hundred eleven million, two hundred four thousand, four hundred seven".
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