3341143413001 has 2 divisors, whose sum is σ = 3341143413002. Its totient is φ = 3341143413000.

The previous prime is 3341143412993. The next prime is 3341143413017. The reversal of 3341143413001 is 1003143411433.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1675626691600 + 1665516721401 = 1294460^2 + 1290549^2 .

It is a cyclic number.

It is not a de Polignac number, because 3341143413001 - 2³ = 3341143412993 is a prime.

It is a super-2 number, since 2×3341143413001² (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3341143413701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670571706500 + 1670571706501.

It is an arithmetic number, because the mean of its divisors is an integer number (1670571706501).

Almost surely, 2^{3341143413001} is an apocalyptic number.

It is an amenable number.

3341143413001 is a deficient number, since it is larger than the sum of its proper divisors (1).

3341143413001 is an equidigital number, since it uses as much as digits as its factorization.

3341143413001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 3341143413001 its reverse (1003143411433), we get a palindrome (4344286824434).

The spelling of 3341143413001 in words is "three trillion, three hundred forty-one billion, one hundred forty-three million, four hundred thirteen thousand, one".