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3341143413701 is a prime number
BaseRepresentation
bin110000100111101011101…
…010101001001111000101
3102211102002000210021102022
4300213223222221033011
5414220130203214301
611034522230452525
7463250435300042
oct60475352511705
912742060707368
103341143413701
111078a75398715
1245b652204145
131b30b7582302
14b79d84061c9
155bd9de98d1b
hex309ebaa93c5

3341143413701 has 2 divisors, whose sum is σ = 3341143413702. Its totient is φ = 3341143413700.

The previous prime is 3341143413623. The next prime is 3341143413787. The reversal of 3341143413701 is 1073143411433.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2221724397025 + 1119419016676 = 1490545^2 + 1058026^2 .

It is a cyclic number.

It is not a de Polignac number, because 3341143413701 - 218 = 3341143151557 is a prime.

It is a super-3 number, since 3×33411434137013 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3341143413001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670571706850 + 1670571706851.

It is an arithmetic number, because the mean of its divisors is an integer number (1670571706851).

Almost surely, 23341143413701 is an apocalyptic number.

It is an amenable number.

3341143413701 is a deficient number, since it is larger than the sum of its proper divisors (1).

3341143413701 is an equidigital number, since it uses as much as digits as its factorization.

3341143413701 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36288, while the sum is 35.

The spelling of 3341143413701 in words is "three trillion, three hundred forty-one billion, one hundred forty-three million, four hundred thirteen thousand, seven hundred one".