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334121133001217 is a prime number
BaseRepresentation
bin100101111111000011010001…
…1011100011100101000000001
31121211000200001020110002020212
41023332012203130130220001
5322243220040022014332
63142341043550043505
7130243312102536362
oct11376064334345001
91554020036402225
10334121133001217
1197508a82071901
1231582ab74a9595
1311458645490873
145c71798b17b69
1528963cdc9c8b2
hex12fe1a371ca01

334121133001217 has 2 divisors, whose sum is σ = 334121133001218. Its totient is φ = 334121133001216.

The previous prime is 334121133001177. The next prime is 334121133001223. The reversal of 334121133001217 is 712100331121433.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 306914800392256 + 27206332608961 = 17518984^2 + 5215969^2 .

It is a cyclic number.

It is not a de Polignac number, because 334121133001217 - 244 = 316528946956801 is a prime.

It is a super-2 number, since 2×3341211330012172 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (334121133021217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167060566500608 + 167060566500609.

It is an arithmetic number, because the mean of its divisors is an integer number (167060566500609).

Almost surely, 2334121133001217 is an apocalyptic number.

It is an amenable number.

334121133001217 is a deficient number, since it is larger than the sum of its proper divisors (1).

334121133001217 is an equidigital number, since it uses as much as digits as its factorization.

334121133001217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9072, while the sum is 32.

The spelling of 334121133001217 in words is "three hundred thirty-four trillion, one hundred twenty-one billion, one hundred thirty-three million, one thousand, two hundred seventeen".