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33413004044093 is a prime number
BaseRepresentation
bin1111001100011100100100…
…01111001010011100111101
311101022020210200221021211202
413212032102033022130331
513334414313013402333
6155021415552425245
710016003250164312
oct746162217123475
9141266720837752
1033413004044093
11a712414786a03
1238b77b7548225
131584aa9766b1b
148372ab544d09
153ce2378b65e8
hex1e63923ca73d

33413004044093 has 2 divisors, whose sum is σ = 33413004044094. Its totient is φ = 33413004044092.

The previous prime is 33413004044081. The next prime is 33413004044113. The reversal of 33413004044093 is 39044040031433.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22008314455204 + 11404689588889 = 4691302^2 + 3377083^2 .

It is an emirp because it is prime and its reverse (39044040031433) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33413004044093 - 212 = 33413004039997 is a prime.

It is a super-2 number, since 2×334130040440932 (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33413004244093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16706502022046 + 16706502022047.

It is an arithmetic number, because the mean of its divisors is an integer number (16706502022047).

Almost surely, 233413004044093 is an apocalyptic number.

It is an amenable number.

33413004044093 is a deficient number, since it is larger than the sum of its proper divisors (1).

33413004044093 is an equidigital number, since it uses as much as digits as its factorization.

33413004044093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 186624, while the sum is 38.

The spelling of 33413004044093 in words is "thirty-three trillion, four hundred thirteen billion, four million, forty-four thousand, ninety-three".