Search a number
-
+
334130114041 is a prime number
BaseRepresentation
bin1001101110010111011…
…01001110110111111001
31011221110002202110110221
410313023231032313321
520433244302122131
6413255223540041
733066025052113
oct4671355166771
91157402673427
10334130114041
11119781814119
125490b5ba621
132567ba70a69
1412259cd03b3
158a58bb0411
hex4dcbb4edf9

334130114041 has 2 divisors, whose sum is σ = 334130114042. Its totient is φ = 334130114040.

The previous prime is 334130114011. The next prime is 334130114069. The reversal of 334130114041 is 140411031433.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 193358075625 + 140772038416 = 439725^2 + 375196^2 .

It is a cyclic number.

It is not a de Polignac number, because 334130114041 - 213 = 334130105849 is a prime.

It is a super-2 number, since 2×3341301140412 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 334130113997 and 334130114015.

It is not a weakly prime, because it can be changed into another prime (334130114011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167065057020 + 167065057021.

It is an arithmetic number, because the mean of its divisors is an integer number (167065057021).

Almost surely, 2334130114041 is an apocalyptic number.

It is an amenable number.

334130114041 is a deficient number, since it is larger than the sum of its proper divisors (1).

334130114041 is an equidigital number, since it uses as much as digits as its factorization.

334130114041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 334130114041 its reverse (140411031433), we get a palindrome (474541145474).

The spelling of 334130114041 in words is "three hundred thirty-four billion, one hundred thirty million, one hundred fourteen thousand, forty-one".