Base | Representation |
---|---|
bin | 1111001100011100110100… |
… | …00000100101101001011011 |
3 | 11101022021010210022010211201 |
4 | 13212032122000211221123 |
5 | 13334420044404103201 |
6 | 155021440531335031 |
7 | 10016006422430341 |
oct | 746163200455133 |
9 | 141267123263751 |
10 | 33413134441051 |
11 | a71248134a092 |
12 | 38b7833151477 |
13 | 1584aca7911a1 |
14 | 8372c09a9991 |
15 | 3ce244072801 |
hex | 1e639a025a5b |
33413134441051 has 2 divisors, whose sum is σ = 33413134441052. Its totient is φ = 33413134441050.
The previous prime is 33413134441021. The next prime is 33413134441079. The reversal of 33413134441051 is 15014443131433.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 33413134441051 - 25 = 33413134441019 is a prime.
It is a super-2 number, since 2×334131344410512 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 33413134441051.
It is not a weakly prime, because it can be changed into another prime (33413134441021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16706567220525 + 16706567220526.
It is an arithmetic number, because the mean of its divisors is an integer number (16706567220526).
Almost surely, 233413134441051 is an apocalyptic number.
33413134441051 is a deficient number, since it is larger than the sum of its proper divisors (1).
33413134441051 is an equidigital number, since it uses as much as digits as its factorization.
33413134441051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 33413134441051 its reverse (15014443131433), we get a palindrome (48427577572484).
The spelling of 33413134441051 in words is "thirty-three trillion, four hundred thirteen billion, one hundred thirty-four million, four hundred forty-one thousand, fifty-one".
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