Base | Representation |
---|---|
bin | 1001101110011000111… |
… | …00010010111001100101 |
3 | 1011221110221222021000111 |
4 | 10313030130102321211 |
5 | 20433310431420201 |
6 | 413300344213021 |
7 | 33066234654601 |
oct | 4671434227145 |
9 | 1157427867014 |
10 | 334142451301 |
11 | 1197887802aa |
12 | 5491376a171 |
13 | 256814a0409 |
14 | 1225b7c2501 |
15 | 8a59ceab51 |
hex | 4dcc712e65 |
334142451301 has 2 divisors, whose sum is σ = 334142451302. Its totient is φ = 334142451300.
The previous prime is 334142451193. The next prime is 334142451323. The reversal of 334142451301 is 103154241433.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 234595891201 + 99546560100 = 484351^2 + 315510^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-334142451301 is a prime.
It is a super-2 number, since 2×3341424513012 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (334142451001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167071225650 + 167071225651.
It is an arithmetic number, because the mean of its divisors is an integer number (167071225651).
Almost surely, 2334142451301 is an apocalyptic number.
It is an amenable number.
334142451301 is a deficient number, since it is larger than the sum of its proper divisors (1).
334142451301 is an equidigital number, since it uses as much as digits as its factorization.
334142451301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 334142451301 its reverse (103154241433), we get a palindrome (437296692734).
The spelling of 334142451301 in words is "three hundred thirty-four billion, one hundred forty-two million, four hundred fifty-one thousand, three hundred one".
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