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3342366433 = 7477480919
BaseRepresentation
bin1100011100111000…
…0111011011100001
322121221020210210101
43013032013123201
523321121211213
61311354302401
7145553434360
oct30716073341
98557223711
103342366433
11146575140a
12793427a01
134135c7023
14239c877d7
15148670bdd
hexc73876e1

3342366433 has 4 divisors (see below), whose sum is σ = 3819847360. Its totient is φ = 2864885508.

The previous prime is 3342366421. The next prime is 3342366439. The reversal of 3342366433 is 3346632433.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3346632433 = 5647592639.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3342366433 is a prime.

It is a super-2 number, since 2×33423664332 = 22342826744890286978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3342366392 and 3342366401.

It is not an unprimeable number, because it can be changed into a prime (3342366439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 238740453 + ... + 238740466.

It is an arithmetic number, because the mean of its divisors is an integer number (954961840).

Almost surely, 23342366433 is an apocalyptic number.

It is an amenable number.

3342366433 is a deficient number, since it is larger than the sum of its proper divisors (477480927).

3342366433 is an equidigital number, since it uses as much as digits as its factorization.

3342366433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 477480926.

The product of its digits is 279936, while the sum is 37.

The square root of 3342366433 is about 57813.2029297807. The cubic root of 3342366433 is about 1495.1497309793.

Adding to 3342366433 its reverse (3346632433), we get a palindrome (6688998866).

It can be divided in two parts, 33423 and 66433, that added together give a square (99856 = 3162).

The spelling of 3342366433 in words is "three billion, three hundred forty-two million, three hundred sixty-six thousand, four hundred thirty-three".

Divisors: 1 7 477480919 3342366433