Base | Representation |
---|---|
bin | 1111001100110001010011… |
… | …00101010011011110000011 |
3 | 11101100022112022022001200001 |
4 | 13212120221211103132003 |
5 | 13340110111041024103 |
6 | 155030500151540431 |
7 | 10016546115024133 |
oct | 746305145233603 |
9 | 141308468261601 |
10 | 33424133142403 |
11 | a717105880213 |
12 | 38b99a268a717 |
13 | 1585b613526b3 |
14 | 837a4561cac3 |
15 | 3ce68995701d |
hex | 1e6629953783 |
33424133142403 has 2 divisors, whose sum is σ = 33424133142404. Its totient is φ = 33424133142402.
The previous prime is 33424133142373. The next prime is 33424133142409. The reversal of 33424133142403 is 30424133142433.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 33424133142403 - 29 = 33424133141891 is a prime.
It is a super-2 number, since 2×334241331424032 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (33424133142409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16712066571201 + 16712066571202.
It is an arithmetic number, because the mean of its divisors is an integer number (16712066571202).
Almost surely, 233424133142403 is an apocalyptic number.
33424133142403 is a deficient number, since it is larger than the sum of its proper divisors (1).
33424133142403 is an equidigital number, since it uses as much as digits as its factorization.
33424133142403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 248832, while the sum is 37.
Adding to 33424133142403 its reverse (30424133142433), we get a palindrome (63848266284836).
The spelling of 33424133142403 in words is "thirty-three trillion, four hundred twenty-four billion, one hundred thirty-three million, one hundred forty-two thousand, four hundred three".
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