Base | Representation |
---|---|
bin | 100110000000100110100011… |
… | …0000001111010111110000010 |
3 | 1121211210001022012100120000110 |
4 | 1030001031012001322332002 |
5 | 322310213133404200310 |
6 | 3143023021421332150 |
7 | 130264566656334222 |
oct | 11401150601727602 |
9 | 1554701265316013 |
10 | 334334314131330 |
11 | 97590428282167 |
12 | 315b8291407056 |
13 | 1147278a55cac6 |
14 | 5c7bc1d634082 |
15 | 289bc09501d20 |
hex | 130134607af82 |
334334314131330 has 64 divisors (see below), whose sum is σ = 824551101220608. Its totient is φ = 86697548087040.
The previous prime is 334334314131319. The next prime is 334334314131451. The reversal of 334334314131330 is 33131413433433.
It is a super-2 number, since 2×3343343141313302 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 82485841 + ... + 86444100.
It is an arithmetic number, because the mean of its divisors is an integer number (12883610956572).
Almost surely, 2334334314131330 is an apocalyptic number.
334334314131330 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
334334314131330 is an abundant number, since it is smaller than the sum of its proper divisors (490216787089278).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
334334314131330 is a wasteful number, since it uses less digits than its factorization.
334334314131330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 168931771.
The product of its (nonzero) digits is 419904, while the sum is 39.
Adding to 334334314131330 its reverse (33131413433433), we get a palindrome (367465727564763).
The spelling of 334334314131330 in words is "three hundred thirty-four trillion, three hundred thirty-four billion, three hundred fourteen million, one hundred thirty-one thousand, three hundred thirty".
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