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3343412443433 is a prime number
BaseRepresentation
bin110000101001110010111…
…010010011100100101001
3102211121221011100221001112
4300221302322103210221
5414234302041142213
611035535324000105
7463360606602056
oct60516272234451
912747834327045
103343412443433
111079a2a1862a7
1245bb86090035
131b33896a295a
14b7b718d202d
155be8329dea8
hex30a72e93929

3343412443433 has 2 divisors, whose sum is σ = 3343412443434. Its totient is φ = 3343412443432.

The previous prime is 3343412443429. The next prime is 3343412443457. The reversal of 3343412443433 is 3343442143433.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2541193068544 + 802219374889 = 1594112^2 + 895667^2 .

It is a cyclic number.

It is not a de Polignac number, because 3343412443433 - 22 = 3343412443429 is a prime.

It is a super-2 number, since 2×33434124434332 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3343412443333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1671706221716 + 1671706221717.

It is an arithmetic number, because the mean of its divisors is an integer number (1671706221717).

Almost surely, 23343412443433 is an apocalyptic number.

It is an amenable number.

3343412443433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3343412443433 is an equidigital number, since it uses as much as digits as its factorization.

3343412443433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1492992, while the sum is 41.

Adding to 3343412443433 its reverse (3343442143433), we get a palindrome (6686854586866).

The spelling of 3343412443433 in words is "three trillion, three hundred forty-three billion, four hundred twelve million, four hundred forty-three thousand, four hundred thirty-three".