Base | Representation |
---|---|
bin | 110000101001110011011… |
… | …100000110110101001111 |
3 | 102211121221210001002122222 |
4 | 300221303130012311033 |
5 | 414234311323213033 |
6 | 11035540241525555 |
7 | 463361045115044 |
oct | 60516334066517 |
9 | 12747853032588 |
10 | 3343421304143 |
11 | 1079a341884a8 |
12 | 45bb890438bb |
13 | 1b338b485a8b |
14 | b7b72b5b1cb |
15 | 5be83e4e598 |
hex | 30a73706d4f |
3343421304143 has 2 divisors, whose sum is σ = 3343421304144. Its totient is φ = 3343421304142.
The previous prime is 3343421304107. The next prime is 3343421304199. The reversal of 3343421304143 is 3414031243433.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3343421304143 - 26 = 3343421304079 is a prime.
It is a super-2 number, since 2×33434213041432 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3343421304343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1671710652071 + 1671710652072.
It is an arithmetic number, because the mean of its divisors is an integer number (1671710652072).
Almost surely, 23343421304143 is an apocalyptic number.
3343421304143 is a deficient number, since it is larger than the sum of its proper divisors (1).
3343421304143 is an equidigital number, since it uses as much as digits as its factorization.
3343421304143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 3343421304143 its reverse (3414031243433), we get a palindrome (6757452547576).
The spelling of 3343421304143 in words is "three trillion, three hundred forty-three billion, four hundred twenty-one million, three hundred four thousand, one hundred forty-three".
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