Base | Representation |
---|---|
bin | 110000101001111010100… |
… | …001011001000011001111 |
3 | 102211122021001122002002121 |
4 | 300221322201121003033 |
5 | 414240032233124444 |
6 | 11040000124433411 |
7 | 463364020116106 |
oct | 60517241310317 |
9 | 12748231562077 |
10 | 3343540129999 |
11 | 1079a95268093 |
12 | 4600009a8867 |
13 | 1b33a9c8b434 |
14 | b7b8484d03d |
15 | 5be8e5c2084 |
hex | 30a7a8590cf |
3343540129999 has 2 divisors, whose sum is σ = 3343540130000. Its totient is φ = 3343540129998.
The previous prime is 3343540129991. The next prime is 3343540130003. The reversal of 3343540129999 is 9999210453433.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3343540129999 - 23 = 3343540129991 is a prime.
It is a super-2 number, since 2×33435401299992 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3343540129991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1671770064999 + 1671770065000.
It is an arithmetic number, because the mean of its divisors is an integer number (1671770065000).
Almost surely, 23343540129999 is an apocalyptic number.
3343540129999 is a deficient number, since it is larger than the sum of its proper divisors (1).
3343540129999 is an equidigital number, since it uses as much as digits as its factorization.
3343540129999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28343520, while the sum is 61.
The spelling of 3343540129999 in words is "three trillion, three hundred forty-three billion, five hundred forty million, one hundred twenty-nine thousand, nine hundred ninety-nine".
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