3350050117 has 2 divisors, whose sum is σ = 3350050118. Its totient is φ = 3350050116.

The previous prime is 3350050091. The next prime is 3350050127. The reversal of 3350050117 is 7110500533.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2459564836 + 890485281 = 49594^2 + 29841^2 .

It is a cyclic number.

It is not a de Polignac number, because 3350050117 - 2¹¹ = 3350048069 is a prime.

It is a super-2 number, since 2×3350050117² = 22445671572823427378, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3350050091 and 3350050100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3350050127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1675025058 + 1675025059.

It is an arithmetic number, because the mean of its divisors is an integer number (1675025059).

Almost surely, 2^3350050117 is an apocalyptic number.

It is an amenable number.

3350050117 is a deficient number, since it is larger than the sum of its proper divisors (1).

3350050117 is an equidigital number, since it uses as much as digits as its factorization.

3350050117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1575, while the sum is 25.

The square root of 3350050117 is about 57879.6174572707. The cubic root of 3350050117 is about 1496.2945751252.

The spelling of 3350050117 in words is "three billion, three hundred fifty million, fifty thousand, one hundred seventeen".