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335114214133 is a prime number
BaseRepresentation
bin1001110000001100101…
…11010001101011110101
31012000222200111221000111
410320012113101223311
520442303214323013
6413541020343021
733132304551436
oct4700627215365
91160880457014
10335114214133
1111a137268086
1254b450a4a71
13257a7901aca
141231089d48d
158ab52a073d
hex4e065d1af5

335114214133 has 2 divisors, whose sum is σ = 335114214134. Its totient is φ = 335114214132.

The previous prime is 335114214121. The next prime is 335114214157. The reversal of 335114214133 is 331412411533.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 278511618564 + 56602595569 = 527742^2 + 237913^2 .

It is a cyclic number.

It is not a de Polignac number, because 335114214133 - 221 = 335112116981 is a prime.

It is a super-2 number, since 2×3351142141332 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 335114214095 and 335114214104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (335114218133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167557107066 + 167557107067.

It is an arithmetic number, because the mean of its divisors is an integer number (167557107067).

Almost surely, 2335114214133 is an apocalyptic number.

It is an amenable number.

335114214133 is a deficient number, since it is larger than the sum of its proper divisors (1).

335114214133 is an equidigital number, since it uses as much as digits as its factorization.

335114214133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12960, while the sum is 31.

Adding to 335114214133 its reverse (331412411533), we get a palindrome (666526625666).

The spelling of 335114214133 in words is "three hundred thirty-five billion, one hundred fourteen million, two hundred fourteen thousand, one hundred thirty-three".