Base | Representation |
---|---|
bin | 110001001011111110011… |
… | …111101001100000101011 |
3 | 102222010122221211101021222 |
4 | 301023332133221200223 |
5 | 420334433141112021 |
6 | 11104445233452255 |
7 | 466130242660313 |
oct | 61137637514053 |
9 | 12863587741258 |
10 | 3380114004011 |
11 | 1093553265a48 |
12 | 46710941108b |
13 | 1b698829b2c4 |
14 | b9853dac443 |
15 | 5cdd03e06ab |
hex | 312fe7e982b |
3380114004011 has 2 divisors, whose sum is σ = 3380114004012. Its totient is φ = 3380114004010.
The previous prime is 3380114003971. The next prime is 3380114004013. The reversal of 3380114004011 is 1104004110833.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3380114004011 - 230 = 3379040262187 is a prime.
It is a super-2 number, since 2×33801140040112 (a number of 26 digits) contains 22 as substring.
Together with 3380114004013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3380114004013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1690057002005 + 1690057002006.
It is an arithmetic number, because the mean of its divisors is an integer number (1690057002006).
Almost surely, 23380114004011 is an apocalyptic number.
3380114004011 is a deficient number, since it is larger than the sum of its proper divisors (1).
3380114004011 is an equidigital number, since it uses as much as digits as its factorization.
3380114004011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 26.
Adding to 3380114004011 its reverse (1104004110833), we get a palindrome (4484118114844).
The spelling of 3380114004011 in words is "three trillion, three hundred eighty billion, one hundred fourteen million, four thousand, eleven".
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